Silver Streak wrote:
The "torque slave" assembly on the driven pulley has pins in angled slots on the shaft that I've always assumed allow it to respond to changes in torque in changing the opening of the real pulley halves. I've never seen a definitive description of how this works, but I'm surmising that it opens the pulley when the torque demand on the rear wheel increases, lowering the gearing. In other words, the gear ratio is sensitive to what is happening at both ends of the drive train, the engine rpms AND the torque demand at the rear wheel.
I guess you could call that magic.

After a weekend of thoughts (and a 500km (about 300miles) trip in my MP3), here it goes. I still doesn't get the whole picture, but maybe with everyone help we can figure it out. I also made some drawings. See bottom.
Also, I couldn't imagine how the spring in the driven pulley could detect the ratio. However, I could see the rollers having a crucial part in this.
For a 1st approach I considered the following simplifications:
1) CVT in higher ratio possible (belt can't go deeper in the driven pulley) - this way, the force generated by the driven pulley spring is not taken into account.
2) the belt only pulls in the top. The bottom part of the belt is left «hanging» - like a bike chain. I don't know if this is a simplification, or if this is really what happens. That's why the bottom part of the belt has that slang
Now, let's try to explain.
Pic 1: I considered that the drive pulley just work in the top quarter. That's the place where all the forces are applied and transmitted, from the pulleys to the belt and from the belt to the pulley.
Pic 2: What happens when you accelerate? You generate a momentum (torque). I represented some of the forces of this momentum. The «Inertial Force» means the force generated by the driven pulley, which try to resist the increase in acceleration.
Pic 3: Those 3 forces (F1, F2 and F3) are the part of momentum which is transmitted to the belt.
Pic 4: I just decompose those forces in their vertical and horizontal components. It should be decomposed in the same direction as the inertial force, but all the drawings were made when I insert the inertial force (sorry).
Pic 5: In the active area, we have a sum of forces applied which are of opposite direction than that of the «inertial force».
So, following my initial idea of the belt sinking in the pulleys, when you start in a static equilibrium of the system, the torque generated is equal to the inertial force. When you accelerate, the torque force is higher than the inertial force.
This is where I can «see» the effect, but I can not explain it very well. It seems obvious that the more force you apply to the pulleys, more the belt has to sink, because the centrifugal force generated by the rollers is not enough to counteract the torque anymore. By doing so, the vario changes.
I'm just trying to visualize how this works. A lot of variables were let outside of this approach, and I'm leaving some parts of the system outside. For instance, you may say that the same effect happens in the active area of the driven pulley, and both «sinks» will compensate and nothing will happen.
Well... is this just a pile of rubbish or makes sense to someone?
Phil
P.S. Couldn't find anything useful in all the internet searches I made. The belt CVT starts to seem a very complex and understudied thing.